| 標準/拡張機能 | C/C++ | 依存項目 |
|---|---|---|
z/OS®UNIX |
両方 | OS/390 V2R10 |
#include <stdio.h>
long long lldiv(long long numer, long long denom);numerator を denominator で割った商および剰余を計算します。
商 long long quot と剰余 long long rem の両方を含む、lldiv_t 型の構造体を戻します。
値を表せない場合は、未定義な戻り値が戻される結果となります。denominator が 0 の場合は、ゼロ除算例外が起こります。
/*
This example uses the
lldiv() function to calculate the quotients and
remainders for a set of two dividends and two divisors.
*/
#define _LONG_LONG 1
#include <stdio.h>
#include <stdlib.h>
int main(void)
{
long long num[2] = {45,-45};
long long den[2] = {7,-7};
lldiv_t ans; /* lldiv_t is a struct type containing
two long long int fields:
'quot' stores quotient; 'rem' stores remainder */
short i,j;
printf("Results of long division:¥n");
for (i = 0; i < 2; i++)
for (j = 0; j < 2; j++)
{
ans = lldiv(num[i], den[j]);
printf("Dividend: %6lld Divisor: %6lld", num[i], den[j]);
printf(" Quotient: %6lld Remainder: %6lld¥n", ans.quot,
ans.rem);
}
} Results of long division:
Dividend: 45 Divisor: 7 Quotient: 6 Remainder: 3
Dividend: 45 Divisor: -7 Quotient: -6 Remainder: 3
Dividend: -45 Divisor: 7 Quotient: -6 Remainder: -3
Dividend: -45 Divisor: -7 Quotient: 6 Remainder: -3