Card order can influence the order of evaluation sets
When an evaluation set is selected, card object names are ordered by their position in the map: card 1 before card 2, and so on. The card order for a map can affect the order of output results.
For example, suppose you want to evaluate the following map rule.
NumberSet ( s ) = B:Card2 + A:Card1
In this example, an evaluation set for this rule consists of one value for B and one value for A. One evaluation set produces one NumberSet.
| A Values | B Values |
|---|---|
| 1 | 3 |
| 2 | 2 |
| 3 | 1 |
There are nine evaluation sets. The order of the cards might affect the order of the evaluation sets.
| Evaluation # | A | B | Result |
|---|---|---|---|
| 1 | 1 | 3 | 4 |
| 2 | 2 | 3 | 5 |
| 3 | 3 | 3 | 6 |
| 4 | 1 | 2 | 3 |
| 5 | 2 | 2 | 4 |
| 6 | 3 | 2 | 5 |
| 7 | 1 | 1 | 2 |
| 8 | 2 | 1 | 3 |
| 9 | 3 | 1 | 4 |
| Evaluation # | B | A | Result |
|---|---|---|---|
| 1 | 3 | 1 | 4 |
| 2 | 2 | 1 | 3 |
| 3 | 1 | 1 | 2 |
| 4 | 3 | 2 | 5 |
| 5 | 2 | 2 | 4 |
| 6 | 1 | 2 | 3 |
| 7 | 3 | 3 | 6 |
| 8 | 2 | 3 | 5 |
| 9 | 1 | 3 | 4 |
If both A and B are contained in the same card object, evaluation sets are selected based on the order A and B appear in the rule. Leftmost objects are selected first. If you change the rule to this:
NumberSet ( s ) = B:Card2 + A:Card2the same results are produced as when card 2 is the first card.