Displaying results

Describes how to display results by writing an execute IBM® ILOG® Script block.

The statements presented so far did not specify what elements of the solution should be displayed. OPL offers a way to display the results of an application. An interesting feature of OPL is the ability to display tuples of expressions.

To display results using an execute block:

Add the following IBM ILOG Script execute block to the product.mod file (see The production-planning problem revisited (product.mod))


tuple R { float x; float y; };
{R} Result = { <Inside[p],Outside[p]> | p in Products };
execute { writeln("Result=",Result); }

You see the following output:


Optimal solution found with objective: 372
result= {<40.0000 60.0000> <0.0000 200.0000> <0.0000 300.0000>}

Run the product model with the productn.dat data file shown in Named data for the revised production-planning problem (productn.dat).

You can visualize the inside and outside productions of a product simultaneously.


Final Solution with objective 372.0000:
  inside = [40.0000 0.0000 0.0000];
  outside = [60.0000 200.0000 300.0000];

Named data for the revised production-planning problem (productn.dat)

Products =  { "kluski", "capellini", "fettuccine" };
Resources = { "flour", "eggs" };

Product = #[
      kluski : 
   #< demand:100
           insideCost:0.6
           outsideCost:0.8
           consumption:[0.5 0.2]
        >#,
      capellini :
   #< demand:200
           insideCost:0.8
           outsideCost:0.9
           consumption:[0.4 0.4]
        >#,
      fettuccine :
   #< demand:300
           insideCost:0.3
           outsideCost:0.4
           consumption:[0.3 0.6]
        >#
          ]#;

Capacity = [ 20, 40 ];

Add the following IBM ILOG Script postprocessing lines to the product.mod file


execute {
   for(p in Products)
     writeln("inside[",p,"].reducedCost = ", inside[p].reducedCost); 
}

You can see both the inside production of a product and its reduced cost.


Optimal solution found with objective: 372 
 inside[kluski].reducedCost = 0 
 inside[capellini].reducedCost = 0.06000000000000005
 inside[fettuccine].reducedCost = 0.02000000000000002