ADD_DAYS
The ADD_DAYS function returns a date or timestamp that represents the first argument plus a specified number of days.
- expression
- An expression that specifies the starting date. The expression must return a value that is of
one of the following built-in data types: a date, a timestamp, a character string, or a graphic
string.
If expression is a character or graphic string, its value must be a valid string representation of a date or timestamp. For the valid formats of string representations of dates and timestamps, see String representations of datetime values.
- numeric-expression
- An expression that specifies the number of days to add to expression. numeric-expression must return a value that is a built-in numeric data type. If the data type of the expression is not BIGINT, it is implicitly cast to BIGINT before evaluating the function. A negative numeric value can be used to subtract days.
If expression is a timestamp, the result of the function is a timestamp with the same precision as expression. Otherwise, the result of the function is a date. If either argument can be null, the result can be null; if either argument is null, the result is the null value.
Examples
- Assume today is January 31, 2007. Set the host variable ADD_DAY with the current day plus 1
day.
SET :ADD_DAY = ADD_DAYS(CURRENT_DATE, 1)The host variable ADD_DAT is set with the value representing 2007-02-01.
- Assume that DATE is a host variable with the value July 27, 1965. Set the host variable ADD_DAY
with the value of that day plus 3
days.
SET :ADD_DAY = ADD_DAYS(:DATE,3)The host variable ADD_DAY is set with the value representing the day plus 3 days, 1965-07-30.
- The ADD_DAYS function and datetime arithmetic can be used to achieve the same results. The
following examples demonstrate
this.
SET :DATEHV = DATE('2008-2-28') + 4 DAYS SET :DATEHV = ADD_DAYS('2008-2-28', 4)In both cases, the host variable DATEHV is set with the value '2008-03-03'.
Now consider the same examples but with the date '2008-2-29' as the argument.
SET :DATEHV = DATE('2008-2-29') + 4 DAYS SET :DATEHV = ADD_DAYS('2008-2-29', 4)In both cases, the host variable DATEHV is set with the value '2008-03-04'.
- Assume that DATE is a host variable with the value July 27, 1965. Set the host variable ADD_DAY
with the value of that day minus 3
days.
SET :ADD_DAY = ADD_DAYS(:DATE, -3)The host variable ADD_DAY is set to 1965-07-24; the value representing July 27, 1965 minus 3 days.

