Tip: Set an XSL style sheet based on XML content

import java.io.File;
import javax.xml.transform.TransformerFactory;
import javax.xml.transform.Transformer;
import javax.xml.transform.stream.StreamSource;
import javax.xml.transform.stream.StreamResult;
import javax.xml.transform.Source;
import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.parsers.DocumentBuilder;
import org.w3c.dom.Document;
import org.w3c.dom.Element;

public class ChooseStyleSheet {
   public static void main (String args[]) {
      String rootName = null;
      try {
         DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
         DocumentBuilder db = dbf.newDocumentBuilder();
         Document doc = db.parse("scores.xml");
         Element root = doc.getDocumentElement();
         rootName = root.getNodeName();
      } catch (Exception e) {
         e.printStackTrace();
      }

      try {

         TransformerFactory transformerFactory = 
                          TransformerFactory.newInstance();

         StreamSource source = new StreamSource("scores.xml");
         StreamResult result = new StreamResult("result.xml");

         String styleName = null;
         if (rootName.equals("results")){
             styleName = "scores.xsl";
         } else if (rootName.equals("entries")){
             styleName = "entries.xsl";
         }

         Transformer transformer = null;
         if (styleName == null) {

             transformer = transformerFactory.newTransformer();

         } else {

             StreamSource style = new StreamSource(styleName);
             transformer =  transformerFactory.newTransformer(style);

         }

         transformer.transform(source, result);

      } catch (Exception e) { 
		e.printStackTrace();
      }
   }
}