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Evaluate mathematical expressions quickly and accurately

With this handy applet, you can evaluate mathematical expressions step by step


Listing 12. Perform the operations

public static double operation_result( double operand1, double operand2, String op )
   {
   double result=0;

   if ( op.equals( "^" ) || op.equals( "**" ) )
      result=Mathematic.pow( operand1, operand2 );
   else if ( op.equals( "*" ) )
      result=Mathematic.multiply( operand1, operand2 );
   else if ( op.equals( "/" ) )
      result=Mathematic.divide( operand1, operand2 );
   else if ( op.equals( "mod" ) )
      result=Math.IEEEremainder( operand1, operand2 );
   else if ( op.equals( "%" ) )
      result=operand1%operand2;
   else if ( op.equals( "+" ) )
      result=Mathematic.add( operand1, operand2 );
   else if ( op.equals( "-" ) )
      result=Mathematic.subtract( operand1, operand2 );
   else if ( op.equals( "<<" ) )
      result=(long)operand1<<(long)operand2;
   else if ( op.equals( ">>" ) )
      result=(long)operand1>>(long)operand2;
   else if ( op.equals( ">>>" ) )
      result=(long)operand1>>>(long)operand2;
   else if ( op.equals( "<" ) )
      result=operand1<operand2 ? 1:0;
   else if ( op.equals( ">" ) )
      result=operand1>operand2 ? 1:0;
   else if ( op.equals( "<=" ) )
      result=operand1<=operand2 ? 1:0;
   else if ( op.equals( ">=" ) )
      result=operand1>=operand2 ? 1:0;
   else if ( op.equals( "==" ) )
      result=operand1==operand2 ? 1:0;
   else if ( op.equals( "!=" ) || op.equals( "<>" ) )
      result=operand1!=operand2 ? 1:0;
   else if ( op.equals( "and" ) )
      result=(long)operand1 & (long)operand2;
   else if ( op.equals( "xor" ) )
      result=(long)operand1 ^ (long)operand2;
   else if ( op.equals( "or" ) )
      result=(long)operand1 | (long)operand2;
   else if ( op.equals( "&&" ) )
      result=(operand1!=0 && operand2!=0) ? 1:0;
   else if ( op.equals( "||" ) )
      result=(operand1!=0 || operand2!=0) ? 1:0;
   return result;
   }

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